Question

# Find sum of even numbers in given range using recursion.

```				```
ENTER THE LOWER RANGE
1
ENTER THE UPPER RANGE
100
Sum of even number between 1 AND 100 :2550
```
```

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Code

```				```
import java.util.Scanner;
public class sum
{
long lowerRange=0,upperRange=0,sum=0;
public void accept()
{
Scanner sc=new Scanner(System.in);
System.out.println("ENTER THE LOWER RANGE");
lowerRange=sc.nextLong();
System.out.println("ENTER THE UPPER RANGE");
upperRange=sc.nextLong();

}

public long findSum(long lowerRange)
{
if(upperRange< lowerRange)
{
return 0;
}
else if(lowerRange%2==0)
{
return lowerRange+findSum(lowerRange+1);
}
else
{
return findSum(lowerRange+1);
}

}

public void display()
{
sum=findSum(lowerRange);
System.out.println("Sum of even number between "+lowerRange+" AND "+upperRange+" :"+sum);
}

public static void main()
{
sum ob1=new sum();
ob1.accept();
ob1.display();

}
}

```
```

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