Question

Check whether a number is a Neon Number

A neon number is a number where the sum of digits of the square of the number is equal to the number. For example, if the input number is 9, its square is 9*9 = 81 and the sum of the digits is 9. i.e. 9 is a neon number.

				
					Enter a number:
9
9 is a Neon Number.

Example 2:
Enter a number:
303
303 is not a Neon Number.

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Code

Java

Python

Java

				
					import java.util.*;
public class NeonNumber
{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the number to check neon number or not");
        int num=sc.nextInt();
        int squaredNumber=num*num;
        int sum=0;
        while(squaredNumber!=0)//Loop to find the sum of digits.
        {
            int a=squaredNumber%10;
            sum=sum+a;
            squaredNumber=squaredNumber/10;
        }
        if(sum==num)
        {
            System.out.println(num+" is a Neon Number.");
        }
        else
        {
            System.out.println(num+" is not a Neon Number.");
        }
    }

}

Python

				
					number=int(input("Enter a number:"))
squareOfNumber=number**2
sumOfDigits=0
while(squareOfNumber>0):
    rem=squareOfNumber%10
    sumOfDigits=sumOfDigits+rem
    squareOfNumber=squareOfNumber//10
if(sumOfDigits==number):
    print(number,"is a neon number")
else:
    print(number,"is not a neon number")