Question

Check whether the given number is Armstrong number or not.

(A positive number is called Armstrong number if sum of its own digits each raised to the power of the number of digits is equal to number)

				
					Enter a number
8208
8^4+2^4+0^4+8^4=4096+16+0+4096
8208 is an armstrong number

Enter a number
153
1^3+5^3+3^3=1+125+27=153
153 is an armstrong number

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Code

Java

Python

Java

				
					import java.util.Scanner;
public class Armstrong
{
    public static void main(String[] args)
    {
        int c=0,r,temp=0,num=0,noOfDigits=0;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number");
        num = sc.nextInt();
        temp=num;
        while(temp>0)
        {
            noOfDigits++;
            temp=temp/10;
        }
        temp=num;
        while(temp>0)
        {
            r=temp%10;
            temp=temp/10;
            c=c+(int)(Math.pow(r,noOfDigits));
        }
        if(num==c)
        {
            System.out.println(num+" is an armstrong number");
        }
        else
        {
            System.out.println(num+" is Not armstrong number");
        }
    }
}

Python

				
					number=int(input("Enter the number:"))
totalDigits=len(str(number))
"""
str(number) converted integer to string 
len() gives length of string
so len(str(number)) combined gives total number of digits 
"""
sum=0
temp=number
while(temp>0):
    digit=temp%10
    sum=sum+digit**totalDigits
    temp=temp//10

if(sum==number):
    print(number,"is Armstrong number")
else:
    print(number,"is not Armstrong number")