Question

# Program to sort non-boundary elements of matrix in descending order .

```				```
Matrix =  [5, 2, 9, 8, 7]
[9, 6, 4, 2, 3]
[3, 8, 1, 3, 9]
[1, 2, 3, 4, 5]

SORTED MATRIX
[5, 2, 9, 8, 7]
[9, 8, 6, 4, 3]
[3, 3, 2, 1, 9]
[1, 2, 3, 4, 5]
```
```

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Code

```				```
import java.util.Scanner;
public class SortNonBoundaryElementsOfMatrix
{
public static void main(String[] args)
{
int row=0,col=0,i=0,j=0,k=0,temp=0,count=0;
int arr[][],b[];

Scanner sc=new Scanner(System.in);
System.out.println("ENTER THE NUMBER OF ROW OF MATRIX");
row=sc.nextInt();
System.out.println("ENTER THE NUMBER OF COLUMN OF MATRIX");
col=sc.nextInt();

arr=new int[row][col];
System.out.println("ENTER THE ELEMENTS IN MATRIX");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
arr[i][j]=sc.nextInt();
/*counting the number of non-boundary elements*/

if(i!=0&&i!=(row-1)&&j!=0&&j!=(col-1))
{
count++;
}
}
}
b=new int[count];
System.out.println("ORIGINAL MATRIX");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
System.out.print(arr[i][j]+" ");

}
System.out.println();
}

for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
if(i!=0 &&j!=0&&i!=(row-1)&&j!=(col-1))
{
b[k]=arr[i][j];
k++;
}
}
}

/*sorting one-dimensional array*/
for(i=0;i< b.length;i++)
{
for(j=0;j< b.length;j++)
{
if(b[i] > b[j])
{
temp=b[i];
b[i]=b[j];
b[j]=temp;
}
}
}

k=0;
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
if(i!=0 &&j!=0&&i!=(row-1)&&j!=(col-1))
{
arr[i][j]=b[k];
k++;
}
}
}

System.out.println("SORTED MATRIX");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
System.out.print(arr[i][j]+" ");

}
System.out.println();
}

}
}

```
```

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