Question
Program to print matrix in spiral order
Matrix
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]
spiral
1 2 3 6 9 8 7 4 5
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Code
import java.util.Scanner;
public class PrintMatrixInSpiralForm
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int arr[][];
int i=0,j=0,top=0,bottom=0,left=0,right=0,row=0,col=0,size=0,count=0;
System.out.println("ENTER NUMBER OF ROWS");
row=sc.nextInt();
System.out.println("ENTER NUMBER OF COLUMNS");
col=sc.nextInt();
arr=new int[row][col];
System.out.println("ENTER ELEMENTS IN ARRAY");
size=arr.length*arr[0].length;
count=0;
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
arr[i][j]=sc.nextInt();
}
}
System.out.println("ORIGINAL MATRIX");
for(i=0;i< row;i++)
{
for(j=0;j< col;j++)
{
System.out.print(arr[i][j]+" ");
}
System.out.println();
}
left=0;
right=col-1;
top=0;
bottom=row-1;
System.out.println("SPIRAL");
/*Checking count < size so that loop stops if we have printed all the digits in array*/
while(count< size)
{
/* This for loop prints from left to right*/
for (i = left; i <= right; i++)
{
/*we are checking count < size inside loop to stop printing if we have printed all the digits*/
if(count< size)
{
System.out.print(arr[top][i] + " ");
count++;
}
}
top++;
/* This for loop prints from up to down*/
for (i=top; i <= bottom; i++)
{
/*we are checking count < size inside loop to stop printing if we have printed all the digits*/
if(count< size)
{
System.out.print(arr[i][right] + " ");
count++;
}
}
right--;
/* This for loop prints from right to left*/
for (i = right; i >=left; i--)
{
/*we are checking count < size inside loop to stop printing if we have printed all the digits*/
if(count< size)
{
System.out.print(arr[bottom][i] + " ");
count++;
}
}
bottom--;
/* This for loop prints from down to up*/
for (i =bottom ; i >= top; i--)
{
/*we are checking count < size inside loop to stop printing if we have printed all the digits*/
if(count< size)
{
System.out.print(arr[i][left] + " ");
count++;
}
}
left++;
}
}
}