Question

Write a menu-driven program to display the pattern as per user’s choice:

Pattern 1

ABCDE

ABCD

ABC

AB

A

Pattern 2
B
L L
U U U
E E E

For an incorrect option, an appropriate error message should be displayed.

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Code

				
					import java.util.Scanner;
public class program8
{
	public static void main(String[]args)
	{	
		int choice=0,i=0,j=0,num=0;
		char k=' ',ch=' ';
		String wd="";
		Scanner sc=new Scanner(System.in);
		System.out.println("Press 1 or 2 to choose a pattern: ");
		choice=sc.nextInt();
		switch(choice)
		{
			case 1:
			    System.out.print("Enter number of lines: ");
                            num = sc.nextInt();
                            for(i=1;i<=num;i++)
			    {	
				k='A';
				for(j=1;j<=num;j++)
				{
					if(j<=num+1-i)
					{
						System.out.print(k);
						k++;
					}
					else
					{
						System.out.print(" ");
					}
				}
				System.out.println();
			    }
			    break;
			case 2:
			    System.out.print("Enter a word: ");
			    wd=sc.next();
				for(i=0;i< wd.length();i++)
				{
				    ch=wd.charAt(i);
			            for(j=0;j< wd.length();j++)
				    {
				        if(j<=i)
			                {
					    System.out.print(ch);
				        }
					else
					{
					    System.out.print(" ");
					}
				    }
				    System.out.println();
				}
				break;
			default:
			    System.out.println("Invalid coice");		
		}
	}
}