Question

Delete odd position element from array

				
					Input:
ENTER THE SIZE OF ARRAY:10
ENTER THE ELEMENT IN THE ARRAY:
1 2 3 4 5 6 7 8 9 10 

ARRAY AFTER DELETING ODD POSITION ELEMENTS:
1 3 5 7 9

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Code

Java

Python

Java

				
					import java.util.Scanner;
public class DeleteOddPositionElementFromArray
{
    public static void main(String[] args)
    {
        /* Initialize array */
        int [] arr;

        int n=0,i=0,j=0,k=0;
        Scanner sc = new Scanner(System.in);

        System.out.println("Enter size of array");
        n = sc.nextInt();
        arr=new int[n];
        System.out.println("Enter numbers in array");

        for(i=0;i< n;i++)
        {
            arr[i]=sc.nextInt();
        }
        for(i=0;i< n;i++)
        {
            if((i+1)%2!=0)
            {
                arr[i]=-999998;
            }
        }

        for(i=0;i< n;i++)
        {
            if(arr[i]==-999998)
            {
                k=i;
                for(j=k+1;j< n;j++)
                {
                    arr[k]=arr[j];
                    k++;
                }
                i=0;
                n=n-1;
            }
        }

        System.out.println("array after deleting odd position");

        for(i=0;i< n;i++)
        {
            System.out.print(arr[i]+" ");
        }
    }
}

Python

				
					size=int(input("Enter the size of List:"))
li=[]
print("Enter Elements in list:")
for i in range(0,size):
    print((i+1),end=": ")
    li.append(int(input()))
count=0
#Print Given Elements
print("Elements in given List:")
print(li)
#counting the odd postitions and
# changing value to "a"
#so that we can remove them easily afterwards
for i in range(0,size,2):
    count=count+1
    li[i]="a"

for i in range(0,count):
    li.remove("a")

#You can also replace from line 14 to line 19 with
#li=[li[i] for i in range(1,size,2)]
#It will do the same thing
print("List after deleting odd positions:")
print(li)