Question

program to find smallest element in diagonals of matrix

Matrix  = [9, 8, 7]
          [6, 5, 4]
          [3, 2, 1]
SMALLEST ELEMENT IN DIAGONALS OF MATRIX:1

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Code

Java

Python

Java

import java.util.Scanner;
public class LargestElementInDiagonalsOfMatrix
{
    public static void main(String[] args)
    {
        int size=0,i=0,j=0,max=0;
        int a[][];


        Scanner sc=new Scanner(System.in);
        System.out.println("ENTER THE SIZE OF MATRIX");
        size=sc.nextInt();

        a=new int[size][size];
        System.out.println("ENTER THE ELEMENTS IN MATRIX");
        for(i=0;i< size;i++)
        {
            for(j=0;j< size;j++)
            {
                a[i][j]=sc.nextInt();
            }
        }

        max=a[0][0];

        for(i=0;i< size;i++)
        {
            for(j=0;j< size;j++)
            {
                if(i==j || (i+j==size-1))
                {
                    if(a[i][j]>max)
                    {
                        max=a[i][j];
                    }

                }
            }
        }
        System.out.println("LARGEST ELEMENT IN DIAGONALS OF MATRIX:"+max);

    }
}

Python

import numpy as np
size=int(input("Enter size of Matrix:"))
matrix=np.empty([size,size],dtype=np.int)
# Taking input from user
print("Enter elements in matrix:")
for i in range(0,size):
    for j in range(0,size):
        print("(",(i+1),",",(j+1),")",":",end="")
        matrix[i,j]=int(input())
#printing the matrix
print("Matrix:")
for i in range(0, size):
    print(matrix[i])
smallestDiagonalElement=matrix[0,0]
#Finding smallest Diagonal elements
for i in range(0,size):
    for j in range(0,size):
        if(i==j or (i+j==size-1)):
            if(matrix[i,j]< smallestDiagonalElement):
                smallestDiagonalElement=matrix[i,j]
print("Smallest Diagonal elements:",smallestDiagonalElement)