Question

Check whether the given number is armstrong number or not in a given range.

A positive number is called armstrong number if sum of its own digits each raised to the power of the number of digits is equal to number

Enter the lower range
1
Enter the Upper range
500
Amstrong Numbers:
1
2
3
4
5
6
7
8
9
153
370
371
407

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Code

Java

Python

Java

import java.util.Scanner;
public class ArmstrongInRange
{
    public static void main(String[] args)
    {
        int c=0,r,temp=0,noOfDigits=0,lowerRange=0,upperRange=0,i=0;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the lower range");
        lowerRange=sc.nextInt();
        System.out.println("Enter the Upper range");
        upperRange=sc.nextInt();
        System.out.println("Amstrong Numbers:");

        for(i=lowerRange;i<=upperRange;i++)
        {
            c=0;
            temp=i;
            noOfDigits=Integer.toString(i).length();
            while(temp>0)
            {
                r=temp%10;
                temp=temp/10;
                c=c+(int)(Math.pow(r,noOfDigits));
            }
            if(i==c)
            {
                System.out.println(i+" ");
            }

        }
    }
}

Python

lowerRange=int(input("Enter the lower Value:"))
upperRange=int(input("Enter the upper Value:"))
print("Armstrong number between",lowerRange,"and",upperRange,":")
for i in range(lowerRange,upperRange+1):
    temp=i
    totalDigits=len(str(i))
    """
        str(i) converted integer to string
        len() gives length of string
        so len(str(i)) combined gives total number of digits
    """
    sum=0
    while(temp>0):
        digit=temp%10
        sum=sum+digit**totalDigits
        temp=temp//10

    if(sum==i):
        print(i,end=" ")